Conversion of data sizes and calculation of data transfer rates

Decimal (SI) Binary (IEC)
1 kB 103 bytes 1 KiB 210 bytes
1 MB 106 bytes 1 MiB 220 bytes
1 GB 109 bytes 1 GiB 230 bytes
1 TB 1012 bytes 1 TiB 240 bytes
1 PB 1015 bytes 1 PiB 250 bytes
1 EB 1018 bytes 1 EiB 260 bytes
1 ZB 1021 bytes 1 ZiB 270 bytes
1 YB 1024 bytes 1 YiB 280 bytes
Calculate the time (days, hours, minutes ...) for the complete data transfer:
t =
d / v
=
100 GiB / 50 MB/s
=
100 x 10243 / 50 x 10002
= 2.147,48s → 35m 47s
t =
d / v
=
850 GiB / 120 MB/s
=
850 x 10243 / 120 x 10002
= 7.605,67s → 2h 6m 45s
t =
d / v
=
40 kB / 3 KiB/s
=
40 x 1000 / 3 x 1024
= 13,02s
t =
d / v
=
110 MiB / 140 kB/s
=
110 x 10242 / 140 x 1000
= 823,88s → 13m 43s
t =
d / v
=
50 MiB / 40 B/s
=
50 x 10242 / 40
= 1.310.720s → 15d 10h 13m
t =
d / v
=
50 kB / 3 MB/s
=
50 x 1000 / 3 x 10002
= 0,016s
t =
d / v
=
50 MBit / 20 kB/s
=
(50 x 10002)/8 / 20 x 1000
= 312,5s → 5m 12s
t =
d / v
=
50 MiBit / 20 kB/s
=
(50 x 10242)/8 / 20 x 1000
= 327,68s → 5m 27s

9. A company is connected to the Internet via DSL connections.
  • Headquarters: symmetrical DSL with 5 MBit/s
  • Store: Asymmetrical DSL with 24 Mbps download, 1 MBit/s upload.
Calculate how much time, in seconds, the transfer of a 3 MiB file from the store to the headquarters will take.
t =
d / v
=
3 MiB / 1 MBit/s
=
3 x 10242 / (1 x 10002)/8
= 25,6s

10. A network with 2 GBit/s should be set up.
  • The current data amount is 4 TiByte
  • The transfer rate of the network is 150 Mbytes/s
Calculate how much time, in hours, minutes and seconds, the transfer will take.
t =
d / v
=
4 TiB / 150 MiB/s
=
4 x 10244 / 150 x 10242
= 27.962,026s → 7h 46m 2s

11. A company database of 4 TB needs to be secured.
  1. The database will be copied to a server, the data transmission should take place over the network (1 Gbit/s). The measured transfer rate is 50 MB/s.
    Calculate how much time, in hours, minutes and seconds, the transfer will take.
  2. It needs to be checked, how many CD's are needed to archive the database.
    Determine the number of CDs required, if the capacity of a CD is 700 MB.
t =
d / v
=
4 TB / 80 MB/s
=
4 x 10004 / 50 x 10002
= 80.000s → 22h 13m 20s
t =
d / v
=
4 TB / 700 MB
=
4 x 10002 / 700
= 5.715 CD's
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